⚖️ Mole Concept & Stoichiometry
Secondary School Chemistry • MalawiHub
1. Introduction
The mole is a convenient unit for counting very large numbers of particles. Stoichiometry is the calculation of the quantities of substances involved in chemical reactions.
Learning Objectives
- Define the mole and Avogadro's constant.
- Calculate relative formula mass.
- Calculate number of moles from mass.
- Use chemical equations to calculate reacting quantities.
- Calculate concentration and gas volumes.
- Determine empirical and molecular formulae.
2. The Mole
One mole contains approximately 6.02 × 10²³ particles.
This number is called Avogadro's constant.
where n = number of moles, m = mass in grams and M = molar mass in g mol⁻¹.
3. Relative Formula Mass
Relative formula mass is found by adding the relative atomic masses of all atoms in the formula.
H = 1, S = 32, O = 16
Mᵣ = (2 × 1) + 32 + (4 × 16)
Mᵣ = 98
4. Calculating Moles from Mass
Mᵣ of H₂O = 18
n = m/M
n = 18/18
n = 1 mol
5. Mole Ratios from Equations
The coefficients in a balanced equation give the mole ratio of the reacting substances.
The ratio is:
1 mol N₂ : 3 mol H₂ : 2 mol NH₃
6. Mass–Mass Calculations
Use the balanced equation to convert from the known substance to the required substance.
CaCO₃ → CaO + CO₂
100 g of CaCO₃ represents 1 mol because Mᵣ(CaCO₃) = 100.
Therefore 100 g CaCO₃ produces 1 mol CaO.
Mᵣ(CaO) = 56.
So the mass of CaO produced is 56 g.
7. Concentration
Concentration in mol dm⁻³ is calculated by dividing moles by volume in dm³.
c = 0.50/2.0
c = 0.25 mol dm⁻³
8. Gas Volumes
At room temperature and pressure, one mole of many gases occupies approximately 24 dm³.
V = 2 × 24
V = 48 dm³
9. Empirical Formula
The empirical formula shows the simplest whole-number ratio of atoms in a compound.
- Convert each mass or percentage to moles.
- Divide all mole values by the smallest value.
- Convert to the simplest whole-number ratio.
- Write the formula.
10. MANEB Examination Focus
- Use correct units.
- Write the balanced equation first.
- Calculate relative formula mass carefully.
- Use mole ratios from the balanced equation.
- Convert cm³ to dm³ when necessary.
- Show working clearly.
Calculate the number of moles in 5.85 g of NaCl. (Na = 23, Cl = 35.5)
n = m/M
n = 5.85/58.5
n = 0.10 mol
11. Practice Exercises
- Calculate Mᵣ of CaCO₃. (Ca=40, C=12, O=16)
- Calculate the moles in 9 g of water.
- Calculate the concentration of 0.20 mol in 500 cm³ of solution.
- What volume does 0.50 mol of gas occupy at RTP?
- Explain why equations must be balanced before stoichiometric calculations.
Answers
- 100
- 0.50 mol
- 0.40 mol dm⁻³
- 12 dm³
- Because the coefficients provide the correct mole ratio between reactants and products.
12. Common Mistakes
- Forgetting to balance the equation.
- Using mass instead of moles in a mole ratio.
- Forgetting to convert cm³ to dm³.
- Giving answers without units.
- Using the wrong relative atomic mass.
13. Exam Tip
For calculation questions, use this order: balanced equation → known moles → mole ratio → required moles → final quantity.